(x^2-3x+4)-(x^2+2x+5)=0

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Solution for (x^2-3x+4)-(x^2+2x+5)=0 equation:


Simplifying
(x2 + -3x + 4) + -1(x2 + 2x + 5) = 0

Reorder the terms:
(4 + -3x + x2) + -1(x2 + 2x + 5) = 0

Remove parenthesis around (4 + -3x + x2)
4 + -3x + x2 + -1(x2 + 2x + 5) = 0

Reorder the terms:
4 + -3x + x2 + -1(5 + 2x + x2) = 0
4 + -3x + x2 + (5 * -1 + 2x * -1 + x2 * -1) = 0
4 + -3x + x2 + (-5 + -2x + -1x2) = 0

Reorder the terms:
4 + -5 + -3x + -2x + x2 + -1x2 = 0

Combine like terms: 4 + -5 = -1
-1 + -3x + -2x + x2 + -1x2 = 0

Combine like terms: -3x + -2x = -5x
-1 + -5x + x2 + -1x2 = 0

Combine like terms: x2 + -1x2 = 0
-1 + -5x + 0 = 0
-1 + -5x = 0

Solving
-1 + -5x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -5x = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -5x = 0 + 1
-5x = 0 + 1

Combine like terms: 0 + 1 = 1
-5x = 1

Divide each side by '-5'.
x = -0.2

Simplifying
x = -0.2

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